For klingon engine range 1 to 5 i found the following formula:
R*(6.17818*10^-9*M^4-2.085*10^-5*M^3+0.02566537*M^2-13.164414*M+2741.939029)=output
R is the skill of the engineering officer (lvl1 =1.000, lvl3 =1.500, lvl4 =1.572, lvl5= 1.715, lvl6= 2.000)
M is the engine mass.
Aenigma